Question

a hammer of 600g, moving at 60ms-¹ strikes a nail.the nail stops a hammer in a very short time of 0.015 what force of nail is on hammer. please answer​

Answer 1

Given:-

• Mass of hammer ,m = 600g = 600/1000 = 0.6kg

• Initial velocity ,u = 60m/s

• Final velocity ,v = 0m/s

• Time taken ,t = 0.015 s

To Find:-

• Force applied by nail on hammer ,F

Solution:-

Firstly we calculate the acceleration of the hammer.

As we know that acceleration is defined as the rate of change of velocity at per unit time.

• a = v-u/t

where,

v is the final velocity

a is the acceleration

u is the initial velocity

t is the time taken

Substitute the value we get

→ a = 0-60/0.015

→ a = -60/0.015

→ a = -4000 m/S²

Here, negative sign show retardation .

Acceleration of the hammer is 4000m/s²

Now, Calculating the Force

• F = ma

Substitute the value we get

→ F = 0.6×4000

→ F = 6×400

→ F = 2400 N

Therefore, the force applied by the hammer on the nail is 2400 Newton.

Answer 2

Given :-

• Mass = 600g = 0.6 kg
• Initial Velocity = 60 m/s
• Time taken = 0.015
• Final velocity = 0 m/s ( because the nail stops )

To Find :-

• Force of nail on hammer

Solution :-

We know,

➩ F = m (v - u)/t

➩ F = 0.6 ( 0 - 60 )/0.015

➩ F = - 0.6 × 60 / 0.015

➩ F = -36/0.015

➩ F = - 2400 N

Force of nail on hammer = -2400 N

Note - * Because the is hammer moving in the opposite direction to that of hammer movement, the negative sign will be used.

*