Question

A hammer of mass 1.5 kg moving at 40 metre per second strikes a nail the nail strips the hammer a very short time of 0.01 seconds what is the force of the nail on the hammer​

Answer 1

$\bigstar GIVEN:$

• Mass (m) = 1.5 Kg.
• Initial velocity (u) = 0ms⁻¹ (This is because the hammer moves from rest).
• Final Velocity (v) = 10ms⁻¹.
• Time (t) = 0.01 Seconds.

$\bigstar FORMULA'S USED:$

$\to a=\frac{(v-u)}{t}$

$\to F=ma$

$\bigstar SOLUTION:$

First, let's find the acceleration so that we can use it in Force formula.

$\to a=\frac{(v-u)}{t}$

$\to a=\frac{40-0}{0.01}$

$\to a= 4000 ms^{-2}$

Then, use this formula:

$\to F=ma$

$\to F=1.5\times 4000$

$\to F=6000 N$

$\therefore FORCE = 6000 N$

${\huge{\mathfrak{\underbrace{\blue{HOPE \:\: THIS \:\: HELPS \:\: :D}}}$