Question

A hammer of mass 1.5 kg moving at 40 metre per second strikes a nail the nail strips the hammer a very short time of 0.01 seconds what is the force of the nail on the hammer​

Answer 1

Answer:

F= 6000 N

Explanation:

As we have

Mass of hammer = m= 1.5kg

Speed of moving hammer= v= 40 m/s

Time for contact force = t= 0.01 sec

Force = F=??

From newton's 2nd law

We have

F= ma

Or

F = m × v/t (a= v/t)

F= 1.5 × (40/0.01)

Solving above expression

We get

F= 6000 N = 6k N