a hammer of mass 1 kg falls freely from a height of 2 m. calculate the kinetic energy of the hammer just before it touches the ground.
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kinetic energy (ke) = 1/2mv^2
kinetic energy (ke)= 1/2×1×9.8×9.8
(note:- 9.8 is the value of (g) gravity ,which is the velocity when a object falls down).
so, answer is/= 48.02
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