A hammer of mass 1 kg moving at 25m/s strikes a nail . The nail stops the hammer in a very short time of 0.02 seconds . What is the force of the nail on the hammer ?
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Answer:
1250N
Explanation:
Mass of the hammer = 1kg
Initial velocity = 25m/s
Final velocity = 0m/s (since it comes to rest)
Time taken to stop the hammer = 0.02 sec
By 2nd law of motion
= m(v - u)/t
= 1(25 - 0)/0.02
= 25/0.02
= 1250N
Force = 1250N
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