Question

A hammer of mass 1 kg with initial velocity 10 m/s hits a
surface and comes to rest in 0.2 second. Find the average
resistive force acting on the hammer and impulse.​

Answer 1

QUESTION-:

A hammer of mass 1 kg with initial velocity 10 m/s hits a  surface and comes to rest in 0.2 second. Find the average  resistive force acting on the hammer and impulse.​

EXPLANATION-:

Mass of hammer=1 kg

Initial velocity(u) of hammer=10 m/s

Final velocity(v) of hammer=0 m/s

Time taken(t)=0.2 s

We know that-:

$\rightarrow \underline{\boxed{\bigstar\;\bf\; Impule=m(v-u)}}\\\\\rightarrow \bf\; Impulse=1(0-10)\\\\\longrightarrow \boxed{\bf\;Impulse=-10\;m/s }$

Now,

Force acting on it will be given that-:

$\rightarrow \underline{\boxed{\bigstar\;\; \bf\; Force=\frac{Impulse}{Time}}}\\\\\rightarrow \bf\; Force=\frac{-10}{0.2}\\\\\longrightarrow \boxed{\bf\; Force=-50\;N}$

∴Force acting is -50 N and Impulse is -10 m/s .