Question

A hammer of mass 1kg falls freely from a height of 2m. Calculate the velocity

Answer 1

$v = \sqrt{2gh}$

$\sqrt{2 \times 10 \times 2}$
$2 \sqrt{10}$
$ke = 1 \div 2mv1v$
$1 \div 2 \times 1 \times 40$
$20joules$
no velocity does not depend on mass

Answer 2

Answer:

v=2√10

Explanation:

PE=mgh

=1×10×2

=20J

KE=PE

KE= 1/2×m×v²

20= 1/2×1×v²

40=v²

v=√40

v=√10×4

v=2√10 m/s