Question

A hammer of mass 1kg moving with a speed of 6m/s strikes a wall and comes to rest in 0.1s. Calculate
(a) Impulse of the force
(b) Average retarding force that stops the hammer.
(c) Average retardation of the hammer

Help chahiye ♥️
(Question from Newtons Law Of Motion)​

Answer 1

Answer:

$\huge\underline\orange{\mathcal Answer}$

(a)Impulse Of The Force :-

$\large{\mathcal Impulse = F ×t}$

$\large{\mathcal Impulse = m(v-u)}$

$\large{\mathcal Impulse = 1(0-6)}$

$\huge{\boxed{\mathcal Impulse = -6Ns}}$

(b) Average Retardation Force that stops the hammer :-

$\large{\mathcal F ={\frac{Impulse}{Time}}}$

$\large{\mathcal F = {\frac{6}{0.1}}}$

$\huge{\boxed{\mathcal F = 60N}}$

(c) Average Retardation :-

$\large{\mathcal a={\frac{F}{m}}}$

$\large{\mathcal a={\frac{60}{1}}}$

$\huge{\boxed{\mathcal a =60m/s2}}$

$\huge\orange{\mathcal Hope\:it\:helps!!!}$

Answer 2

Answer:

60m/s^2

hope helpful......