A hammer of mass 270 g with the speed of 35 m/s, strikes a nail. The nail stops the hammer in a very short time of 0.03 seconds. The force of the nail on the hammer is about
A. 283.5 N
B. 10166 N
C. 315 N
D. 896N
Pls ans fast
Answers
Answered by
0
Explanation:
Mass of the hammer (m) = 500 g = 0.5 kg
The initial velocity of the hammer (u) = 50 m/s
The nail takes time to stop the hammer (t) = 0.01 s
The velocity of the hammer (v) = 0 (since the hammer finally comes to rest)
From Newton’s second law of motion
f = m (v – u) / t
Where f = force
f = 0.5 × (0 – 50) / 0.01
f = -2500 N
Answered by
1
Answer:
The force of nail on the hammer
F=
Time
Change in momentum of hammer
F=
t
m(v−u)
=
0.01
0.5(0−50)
=−2500N
Negative sign denotes that the force of nail on the hammer is acting in the direction opposite to that of motion of hammer.
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