Question

a hammer of mass 300 gram moving at 40 metre per second strikes a nail the nail hanmer in a very short time of 0.02 seconds the force of the nail hammer is​

Answer 1

The force exerted by the nail hammer is -0.24 N

Step-by-step procedure

Given:

Mass of the hammer= 300 gram= 0.3 kg

Initial velocity of the hammer= 40 m/s

Final velocity of the hammer= 0m/s

Time taken to stop the hammer= 0.02 seconds

Solution:

Now, we know that:

Force; F= m× a

F= m( v- u) t

Putting the values in the above equation:

F= 0.3(0- 40)0.02

F= 0.3(-40) 0.02

F= -0.240 N

Result:

Thus, the force exerted by the nail hammer is -0.24 N. The minus sign implied that the direction of movement of the hammer is opposite to the nail.

(#SPJ3)

Answer 2

Answer:

The force of the nail hammer is​ 600N

Explanation:

As per the data given in the question,

We have,

Mass of body= 300 gm= 0.3 kg

Speed at which it is striking (u) i.e. initial velocity = 40m/s

Final velocity after stiking(v)= 0m/s

Time taken by hammer(t) = 0.02 sec

Now, to calculate the acceleration we will use the formula

$v=u+at\\0=40+0.02a\\a=-\frac{40}{0.02}\\a=-2000 (m/s)^{2}$

We know that F=ma

F=$0.3\times (-2000)$ = -600 N

Hence, the force of the nail hammer is​ 600N in opposite direction. "-" indicates the direction.

#SPJ2