Question

A hammer of mass 4 kg falling from a height 50 cm hits a nail partially fixed on a surface and stops in 0.1 s . Find the force

Answer 1

Hey Dear,

◆ Answer -

F = 63.2 N

◆ Explaination -

Velocity of the falling hammer is calculated as -

u = √(2gh)

u = √(2 × 10 × 0.5)

u = √10

u = 3.16 m/s

When the hammer falls on the nail, it's decelerated until it stops.

v = u + at

0 = 3.16 + a × 0.1

a = -3.16/0.1

a = -31.6 m/s^2

Force exerted by nail on the hammer -

F = ma

F = 4 × (-31.6)

F = -63.2 N

Therefore, the force done is 63.2 N in the opposite direction.

Thanks for asking...

Answer 2

Explanation:

हैमर ऑफ़ मास 4kg फॉलिंग फ्रॉम ए हाइट ऑफ 50 सेंटीमीटर इट्स नेम पार्शियली फिक्स्ड ऑन सरफेस एंड स्टॉप्स इन 0.1