Question

A hammer of mass 400 g is moving with at 30 ms-1strikes nail.The nail stops the hammer in a very short time of 0.01s.
What is the force of the nail on the hammer ?


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Answer 1

Answer:

1200 N

Explanation:

force = ma = 0.4 x 30/0.01 = 1200 N

Answer 2

Given,

The mass of the hammer = 400 g

Initial velocity (u) = 0

Final velocity (v) = 30 ms^-1

Time taken = 0.01 seconds

To find out,

The force of the nail on hammer.

Solution:

$\huge \: acceleration(a) = \frac{v - u}{t}$

$a \: = \frac{30 - 0}{0.01} \\ a \: = \frac{30}{0.01} \\ a \: = 3000 \: m {s}^{2}$

Now, using the second law of motion.

Force = mass × acceleration

F = ma

Here, mass (m) = 400 g = 0.4 kg

acceleration (a) = 3000

Force = 0.4 × 3000

Force = 1200 N

Hence the force acting on the nail is 1200N.