A hammer of mass 400g.moving at 30ms-1 strikes a nail. I nail stops the hammer in a very short time of o.01s. What force of nail on the hammer
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Answered by
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F= rate of change of momentum
= m(v-u)/t
=0.4(30-0)/0.1
=120newton
= m(v-u)/t
=0.4(30-0)/0.1
=120newton
Answered by
5
heya...
Here is your answer...
Given,
Initial velocity = 0
Final velocity = 30 m/s^-1
Time taken = 0.01 seconds
Acceleration = v-u/t
= 30-0/0.01
= 30/0.01
= 3000m/s^2
Force = Mass ×acceleration
= 0.4 × 3000
= 1200N
It may help you....☺☺
Here is your answer...
Given,
Initial velocity = 0
Final velocity = 30 m/s^-1
Time taken = 0.01 seconds
Acceleration = v-u/t
= 30-0/0.01
= 30/0.01
= 3000m/s^2
Force = Mass ×acceleration
= 0.4 × 3000
= 1200N
It may help you....☺☺
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