A hammer of mass 5 kg falls from a height of 3m calculate the velocity and the kinetic energy of the hammer just before it touches the ground
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Answer:
The body of 5kg is at a height of 5m. At a height of 5m above geound, it has
Potential energy of body= 5kg×10m/s²×5m = 250 Joule
Since gravity is a conservative force, if we neglect, air friction, the energy of body at any time during the fall would be 250 Joule.
Energy at any instant of time = potential energy at the height at which it is at that instant of time + kinetic energy it has gained at the cost of potential energy in falling through the height= 250 Joule.
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Explanation:
u = mgh
u= 5×10×3
=150
there is an expression for the kinetic energy
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