Question

A hammer of mass 500 g moving at 50 m/s
Strikes a nail. The nail stops the hammer in a
very short time of 0.01s. what is the force of
the nail on the hammer.​

Answer 1

Answer: Mass of the hammer (m) = 500 g = 0.5 kg

The initial velocity of the hammer (u) = 50 m/s

Time is taken by the nail to the stop the hammer (t) = 0.01 s

The velocity of the hammer (v) = 0 (since the hammer finally comes to rest)

From Newton’s second law of motion

f = m (v – u) / t

Where f = force

f = 0.5 × (0 – 50) / 0.01

f = -2500 N

-ve sign indicates the force of nail on the hammer moving in the opposite direction to that of hammer movement.

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Answer 2

Explanation:

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