Question

A hammer of mass 500 g moving at 50m/s strikes a nail. The nail stops the hammer in a very short time equal to 0.015 . What is the force of nail on the hammer ?

Answer 1

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mass = 500g =0.5kg

let initial velocity be. u = 50 m/s

final velocity be v= 0 m/s

time = 0.015

so

F= ma
➢ m ( v-u)/t

so put the value in this equation

F=0.5(0-50)/0.015

F= -(0.5×50×1000)/15

F= -1666.6 N


here -ve sign show that the force is in opposite direction of motion

☛neha Jain 125

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Answer 2

Explanation:

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