Question

a hammer of mass 500 gram moving at 50ms-¹ strikes a nail. The nail stops the hammer in a very short time of 0.01 second. What is the force of the nail of the hammer ?​

Answer 1

$\large{\underline{\mathfrak{\red{Solution:}}}}$

$\large{\boxed{Given}}}}$

M= 500g = 0.5 kg

v = 0 m/s

u = 50 m/s

t = 0.01 s

$</p><p>\large{\boxed{\rm{\blue{Force\:of\: nail\:of\:the\:hammer:-}}}}$

F = m(v-u) / t

F = 0.5 (50-0) / 0.01

F = 0.5 x 50 x 100 / 1

F = 2500 N

$</p><p>\large{\boxed{\rm{\blue{So\:the\: final\:answer\:is\:=>}}}}$

Force of nail = 2500 N

Answer 2

Answer:

$\sf\underline{ \rm {2500 N \: }}$

Explanation:

$\sf{ \rm \blue {mass \: of \: hammer = 500g = \frac{500}{1000}kg }}$

Given:

Initial velocity of the hammer when it strikes the nail, u = 50ms-¹

As the nail stops the hammer ,

So the final velocity of the Hammer v =0

The Time taken, t = 0.01s

To Find :

Force =?

$\sf\{ \rm\orange</u><u> </u><u>\</u><u>underline</u><u>{acceleration,a = \frac{v - u}{t} = \frac{0 - 50}{0.01} = \frac{50 \times 100}{1} = 5000m {s}^{ - 2} }}$

Now, Force exerted by the nail on the hammer

$\sf\underline{ \rm {mass \times acceleration}} \\ = \frac{500}{1000}kg \times 5000 {ms}^{ - 2} \\ = \frac{500}{1000} \times 5000 = 2500N \:$