Question

A hammer of mass 500g, During at 50 m/s, striker a nail. The nails stops the hammer in a very short time of 0.15. what is the force of the nail on the hammer ?

$Physics \ Question}$

Best answer will mark as brainlist ​

Answer 1

$\huge\mathfrak{AnsWer}$

m = 500g = 0.5 kg

v = 0 m/s

u = 50 m/s

t = 0.01 s

F = m(v-u) / t

F = 0.5 (50-0) / 0.01

F = 0.5 x 50 x 100 / 1

F = 2500 N

Force of nail = 2500 N

Answer 2

Answer:

mass =0.5kg

time =.15sec

v=50m/s

force = ma

=0.5(v-u)/t

=1/2(-50)/.15

=-25(100)/15

= -500/3

= -166.67N