Question

A hammer of mass 500g moving at 50 m/s strikes a nail. The nail stops the hammer in a very short time of 0.01s. What is the force of the nail on the hammer

Answer 1

hope the answer is helpful

Answer 2

Answer:

F = -2500 N

Explanation:

Mass of the hammer, m = 500 g = 0.5 kg

Initial velocity of the hammer, u = 50 m/s

Finally, the hammer stops, v = 0

Time taken, t = 0.01 s

The force exerted by the nail on the hammer is calculated using second law of motion as :

$F=m\times (\dfrac{v-u}{t})$

$F=0.5\times (\dfrac{0-50}{0.01})$

F = -2500 N

So, the force exerted by the nail on the hammer is 2500 N in opposite direction. Hence, this is the required solution.