Question

A hammer of mass 500g, moving at 50m/s, strikes a nail. The nail stops the hammer in a very short time of 0.01 s. What is the force of the nail on the hammer?​

Answer 1

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$\huge\bold\purple{Answer:-}$

⏩ Here, m= 500g=0.5 kg, u=50 m/s, v=0, t= 0.01 s.

F= ma= m[v-u/t]

= 0.5[0-50/0.01]

= 0.5× 50/0.01

= 2,500 N

Therefore, magnitude of force of nail on hammer= 2,500 N

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Answer 2

Explanation:

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