Question

A hammer of mass 500g moving at 50m/s strikes a nail. The nail stops the hammer in a very short time of 0.01s. The force of the nail on the hammer is

Answer 1

Explanation:

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Answer 2

Answer:

-2500N

Explanation:

m=500g= $\frac{500}{1000}$ =0.5kg

v=0

u=50m/s

t=0.01s

f=$\frac{m(v-u)}{t}$

f=$\frac{0.5(0-50)}{0.01}$

f= -2500N or -2500kg$m/s^{2}$