Math, asked by ashking00700, 4 months ago

A hammer of mass 500g , moving at 50m/s strikes a nail. The nail stops the hammer in a very short time of 0.01s. What is the force of the nail on the hammer?​

Answers

Answered by nilesh102
0

Given data :

  • A hammer of mass 500 g, moving at 50 m/s strikes a nail.

  • The nail stops the hammer in a very short time of 0.01 sec.

To find : The force of the nail on the hammer ?

Solution : Now, according to given,

→ Mass of hammer = 500 gram

We need to convert in standard S.I unit which is kilogram. Hence,

→ Mass of hammer = 500 gram

→ Mass of hammer = {500/1000} kg

→ Mass of hammer = 0.5 kg

According to given,

→ Initial velocity of hamner = 50 m/s

We know that, hammer will stop after every strike's on nail. Hence,

→ Final velocity of hammer = 0

→ Time taken by hammer to stop = 0.01 sec

Now, we use kinametical equation, to find acceleration by hammer.

→ v = u + a * t

{ where

  • v = final velocity of particle
  • u = initial velocity of particle
  • a = acceleration of the particle
  • t = time taken by particle }

→ v = u + a * t

→ 0 = 50 + a * 0.01 i.e.

→ a * 0.01 = 0 - 50

→ a * 0.01 = - 50

→ a = - 50/0.01

→ a = - 5000 m/s²

Now, by formula of force

→ Force = mass * acceleration

{according to given}

→ Force = 0.5 * ( - 5000 )

→ Force = - 2500 N

Answer : Hence, the force of the nail on the hammer is - 2500 N.

Note : Force can be negative. It means that the force is going to the opposite direction.

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