A hammer of mass 500g , moving at 50m/s strikes a nail. The nail stops the hammer in a very short time of 0.01s. What is the force of the nail on the hammer?
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m = 500g = 0.5 kg
v = 0 m/s
u = 50 m/s
t = 0.01 s
F = m(v-u) / t
F = 0.5 (50-0) / 0.01
F = 0.5 x 50 x 100 / 1
F = 2500 N
Force of nail = 2500 N
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v = 0 m/s
u = 50 m/s
t = 0.01 s
F = m(v-u) / t
F = 0.5 (50-0) / 0.01
F = 0.5 x 50 x 100 / 1
F = 2500 N
Force of nail = 2500 N
Plz mark as brainliest if my answer was helpful …
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