A hammer of mass 500g , moving at 50m/s strikes a nail. The nail stops the hammer in a very short time of 0.01s. What is the force of the nail on the hammer?
Answers
Answered by
19
m = 500g = 0.5 kg
v = 0 m/s
u = 50 m/s
t = 0.01 s
F = m(v-u) / t
F = 0.5 (50-0) / 0.01
F = 0.5 x 50 x 100 / 1
F = 2500 N
Force of nail = 2500 N
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Rv0169:
v is the final velocity which become zero than the impulse generate
this question is based on impulse
so is this answer correct
yes
or
o k
thank you
:)
impulse = change in momentum = force . change in time
tq
Answered by
5
M = 500g = 0.5 kg
v = 0 m/s
u = 50 m/s
t = 0.01 s
F = m(v-u) / t
F = 0.5 (50-0) / 0.01
F = 0.5 x 50 x 100 / 1
F = 2500 N
Force of nail = 2500 N
Plz mark as brainliest if my answer is right
you have copied from other answer
can you make me understand why you have done 50-0 in brackets if v=0m/s ; here----> F = 0.5 (50-0) / 0.01
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