Question

A hammer of mass 500g moving at 6m/s strikes a nail. The nail stips the hammer in a very short time of 0.02 seconds .what is the forced exerted on nail?

Answer 1

Question:

A hammer of mass 500 g moving at 6 m/s strikes a nail. The nail stops the hammer in a very short time of 0.02 seconds .what is the forced exerted on nail?

Given:

• mass of the hammer = 500 g = 0.5 kg

• initial velocity of the hammer =6 m/s

• final velocity of the hammer = 0 m/s

• time taken by the hammer to stop = 0.02 sec

To find:

• force exerted on the nail

Solution :

First we need to find the acceleration of the hammer

By using the first kinematic equation ,

$\bigstar\large\boxed{\mathtt{v=u+at}}$

here,

• v= final velocity
• u = initial velocity
• a= acceleration
• t=time taken

Now substituting the given values in the above equation we get ,

$\rightarrow\mathtt{a=\dfrac{v-u}{t}}$

$\rightarrow\mathtt{a=\dfrac{0-6}{0.02}}$

$\rightarrow\mathtt{a=-300\dfrac{m}{s^{2} }}$

NOTE:The negative sign denotes retardation

__________________________________________________________

Force exerted on the nail is given by the formula ,

$\bigstar\large\boxed{\mathtt{F=ma}}$

here,

• F=force
• m= mass
• a = acceleration

Now substituting the given values in the above equation we get ,

$\rightarrow\mathtt{F=0.5 \times 300}$

$\rightarrow\mathtt{F=150 N}$

The force exerted on the nail is 150 N

Answer 2

The force exerted is 150N


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