A hammer weighing 3kg strikes the head of a nail with a speed of 2ms power-1 divided by 1cm into the wall .calculate the impulse imparted to the wall
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Impulse = Change in momentum
= m(v - u)
= 3 kg × (0 - 2 m/s)
= -6 kgm/s
Impulse imparted to the wall is 6 kgm/s
= m(v - u)
= 3 kg × (0 - 2 m/s)
= -6 kgm/s
Impulse imparted to the wall is 6 kgm/s
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Answer:
6 kg m per second
Explanation:
Impulse is change in momentum
= mv - mu
=3 kg (0-2 m per second)
= 6 kg m per second
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