Question

a hammer with a head of mass 0.5kg strikes a nail at 4m/s and brought to rest. if collision lasts 10^-3, what is the average force on the nail ? compare this force with your weight.
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Answer 1

Explanation:

formula:

F=mv/t

m=0.5 kg

v=4m/s, T=10^-3 s

so,

F=0.5*4/10^-3=2*10^3

so, F=2*10^3N