Question

A handball is tossed vertically upward with a velocity of 19.6 m/s.
Approximately how high will it rise?
A. 15.8 m
B. 19.6 m
c. 25.6 m
D. 30 m
E. 60 m

I need explanation or formula of this question please. ​

Answer 1

Explanation:

hope it will help u....666.....

Answer 2

Given:

Initial velocity = 19.6 m/s

Equations of motion = v = u - gt

Height h = ut - 1/2 * g * t^2

v = final velocity at max. height = 0

g = acceleration due to gravity = 9.8 m/s^2

t = time of motion

Hence we have, 0 = 19.6 - 9.8t

t = 2 s

h = 19.6 * 2 - 1/2 * 9.8 * 4 = 19.6 m

The correct option is "B"

The answer is  19.6m