Question

A handkerchief is 20m long and 18m broad. How much breadth must be decreased
to cover a surface of 324m?​

Answer 1

Answer:

is given that a rectangular hall is 18m 72cm long and 13m 20cm broad which means that rectangular hall is 1872 cm long and 1320 cm broad.

The given integers 1872 and 1320 can be factorised as follows:

1872=2×2×2×2×3×3×13

1320=2×2×2×3×5×11

We know that HCF is the highest common factor, therefore, the HCF of 1872 and 1320 is:

HCF=2×2×2×3=24

Therefore, maximum side of the square is 24 cm and

Since, area of rectangular courtyard is 1872×1320=2471040 and area of the square tile is 24×24=576.

Now, the number of tiles required is:

24×24

1872×1320

=

576

2471040

=4290

Hence, the least possible number of such tiles is 4290.

Answered By

Step-by-step explanation:

this is not your question directed answer but

Answer 2

Area of handkerchief = 18 * 20 = 360

$We \: have \: to \: subtract \\ \: from the \: breadth \: so, taking \: the number \\ \: as \: x, \: which \: we \: will \: subtract \\ \: from \: breadth i.e18$

New eqn = 20 * (18 - x) =324

360 - 20x =324

-20x = -36

x = -36 / -20

x=1.8

So subtracting 1.8 from breadth will cover the surface of 324.