Question

a handle of water pump is 90 cm long from its piston rod

Answer 1

Answer:Let's first calculate mechanical advantage.

Load arm =15 cm  

Effort arm = handle of water pump - load arm = 90 - 15 = 75 cm  

MA = Effort arm/load arm = 75/15 = 5  

 

Thus, effort required to overcome resistance or load of 60 kgf is,  

MA = Load/Effort

Thus,  

Effort = load/ MA = 60 kgf/5 = 12 kgf  

 

Thus, effort = 12 kgf