A hare makes 9 leaps in the same time as a dog makes 5. But the dog's leap is 2m while hare's is only 1 m. How many leaps will the dog have to make before catching up with the hare if the hare has a head start of 16 m?
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1
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I couldn't able to understand your question
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3
Answer:
The dog will have to make 8 leaps
Explanation:
Hare's leap distance = 1 m
Dog's leap distance = 2 m
If hare has a head start of 16 m, then
2*8=16 . Dog will have to jump 8 times.
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