A has fcc arrangement b is present in 2/3 of tetrahedral voids. The formula of the compound will be
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The formula of the compound will be. (a)X4Y3 (b)X2Y3(c)X2Y(d)X3Y4. Clay6 Question ... The number of tetrahedral voids generated = 2N ... Number of atoms of X = 23×2N=23 ...
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