a has got 20% more marks than b then by what percent marks of b are less than the marks of a?
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Let marks of B = x
Marks of A will be = x + 20% of x = x + 20x/100 = 120x/100
Marks of B are less than A by A-B/A * 100
= {(120x/100 - x) / (120x/100)} * 100
= {(20x/100) / (6x/5)} * 100
= {(x/5) / (6x/5)} * 100
= 5/30 * 100
= 50/3 = 16.66%
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