Question

A has some money. If he gives one-fifth of it to B, he is still left with Rs 20 .How much money he had at first?

Answer 1

let total money be 'x'

he gives 1/5th of it to B

remaining money left = x - 1/5
= 4x/5
according to question,
he is left with Rs 20

so that : 4x/5 = 20
: 4x. = 20×5
: 4x. = 100
therefore, x = 100/4
x = 25
hence, he had Rs 25 at first.

Answer 2

A gives to b=1/5
Still 20 is left
X-1/5
4x/5
4x/5= 20
4x =20×5
4x =100
X=100/4
x=25