A has to push a lighter box and B has to push same heavier box on the same floor, who will have to apply larger force and why?
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B as force = mg
since g is constant; and mass is variable B has to apply more force to move the havier object since the floor is same there will be no change in μ i.e. coefficient of friction. havier the object is more is the force required
since g is constant; and mass is variable B has to apply more force to move the havier object since the floor is same there will be no change in μ i.e. coefficient of friction. havier the object is more is the force required
24khanak:
which class are you i anyways?
mg acts downwards and if they are moving the boxes that means they are applying horizontal force and we cannot equate horizontal and vertical force.
i am in 12 u??
oh you mean in that way
same here
nice
by the second law of motion f= ma here a is h
i think we should not waste time and just study
g*
kk
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Answer:
- B has to apply more force as compared to A.
- The heavier box will exert a greater force on the floor as compared to the lighter box.
- The force of friction will be greater between the heavy box and the floor than the force between the lighter box and the surface.
- Therefore, a large amount of force will be required to push the heavier box.
- The frictional force is created when two surfaces collide and slide against one another.
- The texture of the surface and the amount of effort required to bring them together have a big impact on these forces.
- A heavy object has more inertia than the lighter one.
Learn more about frictional forces at-
https://brainly.in/question/23277682?referrer=searchResults
https://brainly.in/question/1156891?referrer=searchResults
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