Math, asked by engcarrion8519, 1 year ago

A has twice as much money as B and B has 50% more money then C has. If the average money with them is rupees 110 then A have

Answers

Answered by rakeshmohata
3
Total money they have =3×110=330 rupees
Let C have x rupees
So, B will have (x+x/2)=3x/2 rupees
Thus A have =2*3x/2=3x rupees
By the problem,
->3x + 3x/2 + x=330
->(8x+3x)/2=330
->11x=660
So, x =60 rupees
Thus A will have (3×60) = 180 rupees (ans)
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