Question

A HCF (2 5 3 and 440) - 11
and LCM (253,440) - 253xK
then find k?​

Answer 1

If a, b are any two positive numbers

Their hcf(a,b)=h and lcm (a,b)=l then

a×b= h×l

Given

a=253,b=440

l=253×k

h=11

Therefore

h×l=a×b

11×253×R=253×440

k=(253×440)/(11×253)

k=40

HOPE IT HELPS