Question

A healthy young man standing at a distance of 7 metre from 11.8 metre high building sees a kid slipping from the top floor. With what speed (assume that uniform) should he run to catch the kid at the arms height (1.8m)?

Can the question be done by using v2=u2+2aS.or is it necessary to use S=ut+1/2at2.

Answer 1

Answer:

Explanation:

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v2 = u2 + 2as

Answer 2

Answer:

Explanation:

here s = 11.8 -1.8 = 10 m

s = ut + 1/2gt^2

u = 0 here as boy slips;  taking g = 10 m/s2

10 = 1/2* 10* t^2

t =  √2 = 1.414 s

now speed of man = 7/1.414 = 4.95 m/s