Question

A heap of coconuts is divided into groups of 2, 3 and 5 and each time one coconut is left over. The least number of Coconuts in the heap is ?

A) 63 B) 31 C) 16 D) 27

Answer 1

Answer:

31

Step-by-step explanation:

From the first statement we can say that the number of coconuts in the heap should be divided by 2 3 and 5 so that every single coconut will be divided and there will be no left over coconut in the heap. So the answer will be L.C.M= 2*3*5=30. The least number of coconut in the heap is 31.

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