a heap of rice in the form of cone of base diameter 24m and height 3.5m find the volume of the rice how much canvas cloth is required to just cover the heap
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Answered by
426
Did you look up to the Leaked question paper of maths ?? because you posted this question a day before Maths cbse class 10 exam
anyways,
Volume = 1/3πr2h
1/3 × 22/7 × 12×12×3.5
= 528 m3
Canvas of cloth required = CSA Of cone
l = √144+12.25
=25/2=12.5m
CSA = 3.14×12×12.5
=471 m2
anyways,
Volume = 1/3πr2h
1/3 × 22/7 × 12×12×3.5
= 528 m3
Canvas of cloth required = CSA Of cone
l = √144+12.25
=25/2=12.5m
CSA = 3.14×12×12.5
=471 m2
subratsahu737:
Here CSA is wrong
ok sorry , can you tell me what would be the correct procedure
CSA=471.4 CM³ (correct)
the power of cube is denoted the volume of anything... here we have to find csa (curved surface area) and for area the unit square is used, here u use or by misprint (3) cube. i hope u undrstnd nd sry for interfer btwn of two u
sorry for my wrong answer ,ty for clarifying my mistake
mention not bro
sry for that bt it is not for u AaushBista, this is for Subratsahu, he did mistaken no u!
I know right , i was actually thanking Subratshu only however you did noticed he wrote wrong unit...
ohh!! wlcm
thanxx
Answered by
320
Volume of rice = volume of cone = 
Here , r = 12 [ ∵ diameter = 24 m ] and h = 3.5m
Now, volume of rice = 1/3 × 22/7 × (12)² × 3.5 m³
= 1/3 × 22/7 × 12 × 12 × 7/2 m³
=22 × 24 = 528 m³
Again, area of canvas cloth = curve surface area of cone = πrl
Here l =
= √{12² + 3.5²} = √{144 + 12.25 } = √{156.25} = 12.5 m
∴ area of canvas cloth = 22/7 × 12 × 12.5 m²
= 471.42 m²
Here , r = 12 [ ∵ diameter = 24 m ] and h = 3.5m
Now, volume of rice = 1/3 × 22/7 × (12)² × 3.5 m³
= 1/3 × 22/7 × 12 × 12 × 7/2 m³
=22 × 24 = 528 m³
Again, area of canvas cloth = curve surface area of cone = πrl
Here l =
= √{12² + 3.5²} = √{144 + 12.25 } = √{156.25} = 12.5 m
∴ area of canvas cloth = 22/7 × 12 × 12.5 m²
= 471.42 m²
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