A heap of rice is in the form of a cone of diameter 12m and height 8m find its volume ? How much canvas cloth is required to cover the heap? (use pi r = 3.14)
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Answer:
Volume = 301.44 m^3
Area of canvas cloth = 188.4 m^2
Step-by-step explanation:
Volume of the heap is the volume of the cone.
Volume of a cone = ( 1 / 3 ) × π × r^2 × h
Given:
π = 3.14
r = 12 / 2 = 6 m
h = 8 m
Volume :
( 1 / 3 ) × 3.14 × 6^2 × 8
= ( 1 / 3 ) × 3.14 × 36 × 8
= 301.44 m^3
The area of the canvas cloth will be equal to the LSA of the conical heap.
TSA of a cone = π × r × l
Given :
π = 3.14
r = 12 / 2 = 6 m
l = √ ( r^2 + h^2 ) = √ ( 6^2 + 8^2 )
= √ ( 36 + 64 ) = √ 100 = 10 m
Thus, area of canvas cloth:
3.14 × 6 × 10 = 188.4 m^2
akash1103:
you made a mistake, TSA of cone is πr(r+l)
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