Question

A heap of rice is in the form of a cone of diameter 16m and height 6m.find its volume? how much canvas cloth is required to cover the heap(use pie =3.14)​ ​

Answer 1

Step-by-step explanation:

Volume of heap of rice

$\frac{1}{3} \pi {r}^{2} h$

Volume of heap of rice=1/3×3.14×8×8×6

Volume of heap of rice=3.14×8×8×2

Volume of heap of rice=401.92 cm^3

Canvas cloth required=C.S.A of heap of the rice

$\pi \: r \: l$

Canvas cloth required=3.14×8×6

Canvas cloth required=150.72 cm^2

=151 cm^2 {approx}

$mark \: this \: as \: branliest$

Answer 2

volume of the heap =  401.92 m ³

canvas cloth is required to cover the heap =  251.2 cm ²

Step-by-step explanation:

diameter of the cone = 16 m

radius of the cone = 8 m

height of the cone = 6 m

slant  height of the cone =

$l^2 = r^2 + h^2\\l = \sqrt{ r^2 + h^2} \\l = \sqrt{ 8^2 +6^2}\\ l = \sqrt{100}\\l = 10$

then

volume of the heap of rice = $\frac{1}{3}\pi r^2h$

volume = $\frac{1}{3}\times 3.14 \times 8\times 8 \times 6$

volume = $\frac{1205.76}{3}$

volume = 401.92 m ³

canvas cloth is required to cover the heap = curved surface area of the cone = $\pi rl$

= $3.14\times 8\times 10$

= 251.2 cm ²

hence ,

volume of the heap =  401.92 m ³

canvas cloth is required to cover the heap =  251.2 cm ²

#Learn more:

A heap of rice is in the form of a cone of diameter 12cm and height 8m.find it's volume? how much canvas cloth is required to cover the heap?

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