A heap of rice is in the form of cone of diameter 24m and height 3 .5 m Find the volume of the rice. How much canvas cloth is required to just cover the heap
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Hi.
Acc. to question,
dimeter of the cone = 24 m
therefore, radius of the cone [r] = 12 m
height [h] of the cone = 3.5 m
Volume of the cone or heap = 1/3 π r× r × h
= 1/3 × 22/7 × 12 × 12 × 3.5
= 528 cubic meter.
Volume of the rice = Volume of the cone or heap
= 528 cubic meter.
slant height [L] =12.5 [ after the calculation from Pythagoras Theorm]
L square = r square + h square
L square = 144 + 12.25
L =12.5
Curved Surface Area of the heap [CONE] = πrl
=22/7× 12 × 12.5
=3300/7
= or[471.4286]
Now, area of canvas = Curved Surface Area of the heap or cone
= 3300/7 square meter.
= or[471.4286]
Hope this will help u.
If u have more query, u can ask me.
Please mark this answer as brainlist.
Acc. to question,
dimeter of the cone = 24 m
therefore, radius of the cone [r] = 12 m
height [h] of the cone = 3.5 m
Volume of the cone or heap = 1/3 π r× r × h
= 1/3 × 22/7 × 12 × 12 × 3.5
= 528 cubic meter.
Volume of the rice = Volume of the cone or heap
= 528 cubic meter.
slant height [L] =12.5 [ after the calculation from Pythagoras Theorm]
L square = r square + h square
L square = 144 + 12.25
L =12.5
Curved Surface Area of the heap [CONE] = πrl
=22/7× 12 × 12.5
=3300/7
= or[471.4286]
Now, area of canvas = Curved Surface Area of the heap or cone
= 3300/7 square meter.
= or[471.4286]
Hope this will help u.
If u have more query, u can ask me.
Please mark this answer as brainlist.
Anonymous:
why u have reported my answer, what is the mistake in that
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