Question

A heap of shots when made up into groups of 28,32 and 42 leaves always a remin 5 shots. find the least number of shots contained in the heap.​

Answer 1

$\huge \mathfrak \red{Solution:}$

$\fbox \pink{Step 1:}$

First let us find the LCM of the number of shots in the heap.

So, the LCM of 28, 32 and 42 is 672.

$\fbox \green{Step 2:}$

Now, to find the least number of shots contained in the heap, we subtract the remainder from the LCM we found, which is 672 - 5

$\fbox \blue{Final Answer:}$

The least number of shots in the heap is 667