A heap of wheat is in form of cone whose diameter is 10 and height is 3m find it volume of 1cm³ wheat cost is ₹ 10, then find the total cost
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Diameter of cone = 10.5 m
Radius of cone (r) = 5.25 m
Height of cone (h) = 3 m
Volume of cone = 1 / 3 πr2h
= 1 / 3 × 22 / 7 × 5.25 × 5.25 × 3
= 86.625m3
Cost of 1m3 of wheat = 10
∴ Cost of 86.625 m3 of wheat = 10 × 86.625
= 86.625
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