Question

A heap of wheat is in the form of a cone of diameter 10.5 m and height 7 m

Answer 1

Given : Diameter = 9 m or radius = 9/2 = 4.5 m and h = 3.5 m

Volume of cone = 1/3πr²h

= 1/3*22/7*4.5*4.5*3.5

= 1559.25/21

Volume of the cone = 74.25 cu m

Just to cover the heap, we have to find the curved surface area of the cone. For slant height 'l' is needed.

So, l = √r²+h²

l = √4.5²+3.5²

l = √20.25+12.25

l = √32.5

l = 5.7008 m

Curved surface area of the cone = πrl

= 22/7*4.5*5.7008

= 564.3792/7

CSA of the cone = 80.6256 m²

So, area of the canvas required to cover the heap of wheat is 80.6256 sq m

Answer 2

Answer:

See attachment for answer