A heap of wheat is in the form of a cone of diameter 16•8m and height 3•5m.Find Its volume.How much cloth is required to just cover the heap?
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Volume of heap of wheat=1/3Πr²h
=1/3*22/7*8.4*8.4*3.5
=22*2.8*8.4*0.5
=61.6*4.2
Volume of heap of wheat=258.72m³
Cloth required to cover the heap=CSA of heap
=Πrl
l=√h²+r²
l=√12.25+70.56
l=√82.81
l=9.1 m
Cloth required=22/7*8.4*9.1
=22*1.2*9.1
=26.4*9.1
=240.24m²
=1/3*22/7*8.4*8.4*3.5
=22*2.8*8.4*0.5
=61.6*4.2
Volume of heap of wheat=258.72m³
Cloth required to cover the heap=CSA of heap
=Πrl
l=√h²+r²
l=√12.25+70.56
l=√82.81
l=9.1 m
Cloth required=22/7*8.4*9.1
=22*1.2*9.1
=26.4*9.1
=240.24m²
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