A heap of wheat is in the form of a cone of diameter 9 m and height 3.5 m. Find its volume. How much canvas cloth is required to just cover the heap? (Use * = 3.14.)
Answers
Step-by-step explanation:
It is given that
Diameter of the conical heap =9 m
Radius of the conical heap =9/2
=4.5 m
Height of the conical heap =3.5 m
We know that
Volume of the conical heap =1/3 πr ^2h
By substituting the values
Volume of the conical heap = 1/3×3.14×4.5^2 ×3.5
On further calculation
Volume of the conical heap =3.14×1.5×4.5×3.5
So we get
Volume of the conical heap =74.1825 m^3
We know that
Slant height l=
(r
2
+h
2
)
By substituting the values
l=
(4.5
2
+3.5
2
)
On further calculation
l=
32.5
So we get
l=5.7 m
We know that
Curved surface area of the conical heap =πrl
By substituting the values
Curved surface area of the conical heap =3.14×4.5×5.7
On further calculation
Curved surface area of the conical heap =80.54 m
2
Therefore, 80.54 m
2
of canvas is required to cover the heap of wheat.
ms..g on ins.ta rajeev_5561
Answer:
Diameter of the conical heap = 9m Radius of the conical heap = 9/2 = 4.5m Height of the conical heap = 3.5m We know that Volume of the conical heap = 1/3 πr2h By substituting the values Volume of the conical heap = 1/3 × 3.14 × 4.52 × 3.5 On further calculation Volume of the conical heap = 3.14 × 1.5 × 4.5 × 3.5 So we get Volume of the conical heap = 74.1825 m3 We know that Slant height l =√ (r2 + h2) By substituting the values l = √ (4.52 + 3.52) On further calculation l = √ 32.5 So we get l = 5.7 m We know that Curved surface area of the conical heap = πrl By substituting the values Curved surface area of the conical heap = 3.14 × 4.5 × 5.7 On further calculation Curved surface area of the conical heap = 80.54 m2 Therefore, 80.54 m2 of canvas is required to cover the heap of wheat.Read more on Sarthaks.com - https://www.sarthaks.com/721581/a-heap-of-wheat-is-in-the-form-of-a-cone-of-diameter-9m-and-height-3-5m-find-its-volume