Math, asked by Surajrathour, 1 year ago

A heap of wheat is in the form of a cone, the diameter of whose base is 14m and height is 3m .fine it's volume. the heap it to be covered by canvas to protect it from rain. fine the are area of canvas required

Answers

Answered by Panzer786
11
Hii friend,

DIAMETER = 14 M

RADIUS = D/2 = 14/2 = 7 M

HEIGHT OF THE HEAP = 3 M

THEREFORE,

VOLUME OF THE HEAP = 1/3 πr² h = 1/3 × 22/7 × 7× 7 × 3 = 22 × 7 × 3/3 = 154 M³

AREA OF THE CANVAS REQUIRED FOR COVER THE TOP OF THE HEAP = πr² = 22/7 × 7 × 7 = 22×7 = 154 M².

HOPE IT WILL HELP YOU...... :-)

sivaprasath: Area of canvas required to cover the heap of wheat is CSA of cone, not area of it's base,. We can't put an umbrella-like structure to protect it from rain ,.(lol),. So, you should have used πrl units and find CSA,.
Answered by Anonymous
6
Diameter of Base = 14m
.°. Radius = 14/2 = 7cm

Height of cone = 3m

Latent height = root(3²+7²= 9 +49) =

.°. Volume of cone = ( πr²h ) / 3
= (3.14 * 7 * 7 * 3) / 3
= (3.14 * 49)
=153.86m³

CSA of cone = πrl
= 3.14 * 7 * 7.14
= 156.93 cm²

Hence, the area of canvas required is 156.93cm²

Surajrathour: hi bro
Surajrathour: pls give me a answer this question
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