A heap of wheat is in the form of a cone whoose diameter is 10.5 m and height is 3m.find its volume. the heap is to be covered by canvas to protect it from rain .find the area of the canvas required
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Diameter=10.5m
radius=10.5/2m
height=3m
Volume= 1/3πr^2h
= 1/3×22/7×10.5/2×10.5/2×3
=11×1.5×10.5/2
=86.625m^3
l^2 =r^2+h^2 (where l is slant height of the cone)
=(10.5/2)^2+(3)^2
=(110.25/4)+9
l^2 =146.25/4
l =√146.25/4
l =12/2
l =6m
Area of canvas required=CSA of the cone= πrl
=22/7×10.5/2×6
=11×1.5×6
=99m^2
radius=10.5/2m
height=3m
Volume= 1/3πr^2h
= 1/3×22/7×10.5/2×10.5/2×3
=11×1.5×10.5/2
=86.625m^3
l^2 =r^2+h^2 (where l is slant height of the cone)
=(10.5/2)^2+(3)^2
=(110.25/4)+9
l^2 =146.25/4
l =√146.25/4
l =12/2
l =6m
Area of canvas required=CSA of the cone= πrl
=22/7×10.5/2×6
=11×1.5×6
=99m^2
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